132-faced all-pentagon polyhedron

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wpthomps
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132-faced all-pentagon polyhedron

Post by wpthomps »

Robert,

On August 2, 2016 you shared a post on your RobertLovesPi.net blog titled "Three Polyhedra with Only Pentagonal Faces." Here's a URL to it:

https://robertlovespi.net/2016/08/02/tw ... nal-faces/

I'd also like to create this polyhedron. To Robert and anybody else who's interested, what steps using Stella could one follow to create this 132-pentagon polyhedron?

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Thank you for your time and assistance!
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robertw
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Re: 132-faced all-pentagon polyhedron

Post by robertw »

Seems to be a common mistake, but that page is by Robert Austin, who uses Stella, but this Stella forum and Stella itself are by me, Robert Webb.

So I'm not sure how he made that model, although you may be able to do it by creating a geodesic sphere from an icosahedron and then using faceting mode to create the final faces. But you'd have to experiment with it.
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Re: 132-faced all-pentagon polyhedron

Post by wpthomps »

I apologize for the mix up. Thank you for taking the time to clarify that for me.

Along the lines of your suggestion, I tried faceting a 5-frequency geodesic sphere based off of a dodecahedron as opposed to an icosahedron. Here are screenshots of two facetings. Outlined in black are three pentagonal faces, two of which were unsuccessfully created.

Aside from the 12 new pentagons formed immediately around the vertices of the base dodecahedron, I could not find any other groupings of five vertices that were coplanar. How can one make the points on these two other attempted pentagonal faces coplanar?

I appreciate your help, Robert! In the mean time, I'll keep experimenting.

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robertw
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Re: 132-faced all-pentagon polyhedron

Post by robertw »

Yep getting all the pentagons planar will be an issue. Might be easier to aim for creating the dual instead, which will be mostly triangles with a few quads. Easier to keep them planar then.

I tried some things and ended up having some success. Here's what I did...

(1) Load a rhombicosidodecahedron (Ctrl+N for "new" and find it in the list, or type "rid")

(2) Stellate over the triangles and make it the new base model

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(3) The pentagons are too big here. I want to stellate over them but not all the way, so I added the model to a slightly larger dodecahedron, giving extra planes for the stellation. First I set the scale to 5 (Scale->Base Polyhedron Radius) and put it in a memory slot (Edit->Put Model in Memory->Memory 1, or type "m1"). Load a dodecahedron and set its scale to 6.5 (I tried a few different values). Add it to the previous model (Edit->Add/Blend from Memory). Then select stellation cells again to carve out the desired shape. Make this the new base model.

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(4) Looking good, b ut we need to subdivide the hexagons into 4 pentagons. I found subdividing faces to level 6 was a good starting point. Then use faceting mode to create the faces. Accept the faceting, saying "No" to blending faces.

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The faceting looks pretty good, but some of the pentagons are coplanar.

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(5) I tried using the spring model to make faces closer to regular. It gave an interesting result but not what we want:

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(6) Instead, I decided to make the dual we want. Select each face type in turn (3 of them) and augment with a pyramid, stretching each pyramid out a bit. We want all the peaks to lie roughly on a sphere (doesn't need to be exact). I got this:

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(7) Create the convex hull and look at the dual

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(8) It's what we want, but could be better. Make sure the base view is selected (just click in it) and use "Poly->Project Onto Sphere". This improves the dual a bit

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Not bad. There's a few choices a long the way that could improve it. Maybe try 6.6 or 6.7 in step 3 (7.0 was too much). And maybe better not to stretch the pyramids as far as I did in step 6.

No doubt Robert Austin's method was simpler!
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Re: 132-faced all-pentagon polyhedron

Post by robertw »

By the way, don't know if you've seen my MineSweeper3D game, but for N-gons with N >= 5 I subdivide the faces using pentgagons in a similar way. There's one N-gon left in the centre and the rest are pentagons (all pentagons when N = 5).

This image shows 2 levels of subdivision.

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