Search found 148 matches

by Ulrich
Fri Jul 28, 2017 10:29 am
Forum: Stella Forum
Topic: Tutorial: how to make this thing
Replies: 3
Views: 9402

works fine, thanks!


Image
by Ulrich
Fri Jul 28, 2017 6:36 am
Forum: Stella Forum
Topic: Tutorial: how to make this thing
Replies: 3
Views: 9402

Robert,

how do you get the six spheres blue in the original Picture?

Ulrich
by Ulrich
Sun Jun 25, 2017 9:38 am
Forum: Stella Forum
Topic: Faceting
Replies: 6
Views: 11627

You cannot upload pictures in this forum directly, you have to put a link to a file you uploaded to your website or to photobucket or something like that. Before creating a new model from facetings make sure that you chose a layout with at least 2 windows (hit ctrl+2). Then you have the base model i...
by Ulrich
Thu Mar 09, 2017 8:12 am
Forum: Stella Forum
Topic: How to Distort Heptogrammic Pyramid
Replies: 2
Views: 7650

You select the heptagrammic face, hit: scale->stretch (non-uniform scale)..., enter the desired value (scale by or set value to ...) and "perpendicular to selected face".

Ulrich
by Ulrich
Fri Mar 03, 2017 12:50 pm
Forum: Stella Forum
Topic: Breakup face
Replies: 4
Views: 11214

If you want to colour each spike of a shape like the great stellated dodecahedron individually you can open it in the base stellation view, put it into a memory, retrieve it again, activate the base polyhedron view and give each triangular face the colour you want by hitting Ctrl+c.

Ulrich
by Ulrich
Fri Mar 03, 2017 11:27 am
Forum: Stella Forum
Topic: Identify This?
Replies: 2
Views: 8257

I'd call it a rhombic 180-hedron and I guess you'll have to do the colouring by hand using Ctrl+c.

Ulrich
by Ulrich
Fri Feb 10, 2017 11:14 am
Forum: Stella Forum
Topic: Leonardo Great Dodecahedron 2
Replies: 4
Views: 10762

When this model is opened in the library it is displayed in the base stellation view. So you can fix that colour problem easily by putting the model into a memory, retrieving it again and activating the base view. Then you can select the inner parts and give them a different colour by using shift c....
by Ulrich
Thu Feb 09, 2017 8:40 am
Forum: Stella Forum
Topic: Leonardo Great Dodecahedron 2
Replies: 4
Views: 10762

If you have stella fold and unfold the net in the 'folding net view' you see that the net is complete.

Ulrich
by Ulrich
Mon Dec 05, 2016 7:46 am
Forum: Polyhedron Models
Topic: On display in Finland
Replies: 3
Views: 9781

Great!!
by Ulrich
Sun Oct 02, 2016 1:19 pm
Forum: Polyhedra
Topic: Coloring of Snub Dodecahedron
Replies: 3
Views: 16369

If you allow a pentagon and a triangle to share the same colour at one vertex, you get along with four colours:

Image

Ulrich
by Ulrich
Mon Mar 30, 2015 6:51 am
Forum: Polyhedra
Topic: Miller's Monster
Replies: 8
Views: 29043

much easier indeed, cool!
by Ulrich
Sat Mar 28, 2015 8:08 pm
Forum: Polyhedra
Topic: Miller's Monster
Replies: 8
Views: 29043

I tried it in the following way: Take the compound of 5 tetrahedra and put it into memory 1. Then take Millers Monster, select a pentagram (they all should be red in the auto colour option), you hit c and you slightly shift the red colour a bit lighter or darker to avoid colour conflicts in the foll...
by Ulrich
Tue Mar 03, 2015 10:51 am
Forum: Polyhedra
Topic: Compound of 3 Rhombic Prisms
Replies: 12
Views: 34715

robertw wrote:
Pretty magic and cryptic I know! Ideally someday I should make the add-from-memory a bit more clever about orientations!
And doing that, could you please take care of the "put models on faces"-tool too?

Ulrich
by Ulrich
Tue Mar 03, 2015 8:57 am
Forum: Polyhedra
Topic: Compound of 3 Rhombic Prisms
Replies: 12
Views: 34715

But... my problem seems to be the position of the added Rh. Pr. in the cube- as you mentioned already. I work on 2 pc's and both show the Rh.Pr. rotated somehow in the cube. See picture. https://www.dropbox.com/s/0rxfbj63cn1jjro/Screenshot%202015-03-02%2018.05.17.png?dl=0 Too bad for me. Now the ga...
by Ulrich
Mon Mar 02, 2015 11:16 am
Forum: Polyhedra
Topic: Compound of 3 Rhombic Prisms
Replies: 12
Views: 34715

Seems that I was a little too hasty describing the procedure. In the rh prism, there are 8 edges where squares and rhombs meet at 90° and 4 edges where only squares meet. At two of the latter ones, the squares are forming an acute angle (=> "acute edges"), at the other ones the angle is shallow (=>"...