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Gilson: Polyhedra - A New Approach
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oxenholme



Joined: 16 Jan 2008
Posts: 83
Location: North West England

PostPosted: Sun Nov 04, 2012 9:42 pm    Post subject: Reply with quote

removed

Last edited by oxenholme on Mon Nov 05, 2012 4:24 pm; edited 1 time in total
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Ulrich



Joined: 29 Jan 2008
Posts: 87
Location: Germany

PostPosted: Mon Nov 05, 2012 11:07 am    Post subject: Reply with quote

If the lateral pentagons are regular and their edge length is 1, Stella tells me that the other edge length is 4.69217462142686, the acute angle is 29.8878:



metric data:
28 facelets, of 2 types; 70 edgelets; 44 vertices, of 4 types.
Radius 4.83391, Diameter 9.66782
Facelet type 0: area 1.72048
Edge 0-0: Joins 1-1, Length 1, Dihedral 142.09 deg, Mitre 18.9551 deg
Face angle 108 deg
Edge 0-1: Joins 0-1, Length 1, Dihedral 152.938 deg, Mitre 13.5311 deg
Face angle 108 deg
Edge 0-2: Joins 1-0, Length 1, Dihedral 142.09 deg, Mitre 18.9551 deg
Face angle 108 deg
Edge 0-3: Joins 1-2, Length 1, Dihedral 142.09 deg, Mitre 18.9551 deg
Face angle 108 deg
Edge 0-4: Joins 0-4, Length 1, Dihedral 152.938 deg, Mitre 13.5311 deg
Face angle 108 deg
Facelet type 1: area 6.68965
Edge 1-0: Joins 0-2, Length 1, Dihedral 142.09 deg, Mitre 18.9551 deg
Face angle 135.234 deg
Edge 1-1: Joins 0-0, Length 1, Dihedral 142.09 deg, Mitre 18.9551 deg
Face angle 135.234 deg
Edge 1-2: Joins 0-3, Length 1, Dihedral 142.09 deg, Mitre 18.9551 deg
Face angle 119.822 deg
Edge 1-3: Joins 1-4, Length 4.69217, Dihedral 137.658 deg, Mitre 21.1709 deg
Face angle 29.8878 deg
Edge 1-4: Joins 1-3, Length 4.69217, Dihedral 137.658 deg, Mitre 21.1709 deg
Face angle 119.822 deg

Ulrich
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oxenholme



Joined: 16 Jan 2008
Posts: 83
Location: North West England

PostPosted: Mon Nov 05, 2012 4:35 pm    Post subject: Reply with quote

Vive le difference!

I didn't realise Stella could "do" this one.

It is quite amusing seeing all the data correct to umpteen decimal places.

I divided the 360 degrees into 14, and used a couple of spring bow compasses to produce the net for the equatorial pentagons - not measuring any dimensions anywhere.

I pushed a skewer through the centre, and used the ruler as a rigid flat object to determine the height of the 7 sided pyramid. I then took the first and second actual measurements - the long pentagons being 59.3mm in height and 29.7mm in width. Again I used a couple of spring bow compasses to determine the vertices of the long pentagons.

I actually quite like the proportions of the end result.



Last edited by oxenholme on Tue Nov 06, 2012 7:17 am; edited 1 time in total
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guy



Joined: 11 Feb 2008
Posts: 75
Location: England

PostPosted: Mon Nov 05, 2012 10:03 pm    Post subject: Reply with quote

Looks really cool. Congratulations.
_________________
Cheers,
Guy. Guy's polyhedra pages
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Peter Kane



Joined: 25 Oct 2009
Posts: 79
Location: S.E England

PostPosted: Tue Nov 06, 2012 9:18 am    Post subject: Reply with quote

A great ruler & compass & skewer achievement! If only Euclid had been fond of kebabs, he might have produced an Elements 2.

Well done!

Pete K
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